Physics, asked by ujahnavi31, 8 months ago

Three pure inductances each of 31 are
connected as shown in figure. The equivalent
inductance between points A and B is
3H
SH
00000
3 H
16000
000
A
1) IH
2) 2H
3) 3H
4) 9H​

Answers

Answered by ItzMagicalpie
16

Question :-

Three pure inductances each of 31 are

connected as shown in figure. The equivalent

inductance between points A and B is..

1) IH

2) 2H

3) 3H

4) 9H

Answer :-

If we use concept of short circuiting then arrange of inductors as shown in figure.

where,

  • \small{ \sf{L_{1} =  L_{2} = L_{3} = 3H}}

you can see all the resistance are in parallel so, equivalent inductance of inductors is given by

\small{ \sf{   \frac{1}{ L_{eq}} = \frac{1}{L_{1}}   +   \frac{1}{L_{2}} + \frac{1}{L_{3}}}}

\small{ \sf{   \frac{1}{ L_{eq}} = \frac{1}{3H}   +   \frac{1}{3H} + \frac{1}{3H}}}

Leq = 1H

  • hence, option (A) is correct.
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