Question

Three quantities A, B, C are such that AB=KC, where K is
a constant. When A is kept constant, B varies directly as C;
When B is kept constant, A varies directly as C and when C
is kept constant, A varies inversely as B.
Initially, A was at 5 and A:B:C was 1:3:5. Find the value
of A when B equals 9 at constant C.
(a) 8
(b) 8.33
(c) 9
(d) 9.5​

Answer 1

Answer:

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Answer 2

Answer:

initial value 5,15,25

we have 5 x 15=K × 25

k=3

eq AB =3C

KEEP C CONSTANT AT 25

A × 9=3 × 25

A=8.33