Math, asked by sachusoman, 1 year ago

Three racers, Ajay, Bharat and Charan, took part in a race, Ajay completed his race, 20 metres ahead of Bharat and 34 metres ahead of Charan, while Bharat completed his race 21 metres ahead of Charan. While running, no racer could change his speed. What was the distance of race ?


bmohankumar: When A reaches the end, notice that B has already created a distance of 14 m between himself and C. when B reaches the end point, ie. after another 20 m, distance between him and c is 21m ie. another 7 m. so in every 20 m b is creating distance of 7 m between himself and c. to create a distance of 21m between himself and c, he must have to run total of 60m. so the race must be of 60m.

Answers

Answered by bmohankumar
9
When A reaches the end, notice that B has already created a distance of 14 m between himself and C. when B reaches the end point, ie. after another 20 m, distance between him and c is 21m ie. another 7 m. so in every 20 m b is creating distance of 7 m between himself and c. to create a distance of 21m between himself and c, he must have to run total of 60m. so the race must be of 60m.
Answered by Sanav1106
0

Race must be 60m.

GIVEN: Ajay completed his race, 20 meters ahead of Bharat and 34 meters ahead of Charan, while Bharat completed his race 21 meters ahead of Charan.
TO FIND: Distance of Race
SOLUTION:

As we are given in the question,

Ajay completed his race, 20 meters ahead of Bharat and 34 meters ahead of Charan, while Bharat completed his race 21 meters ahead of Charan.

Therefore,

We can conclude,

When Ajay reaches the end, notices that Bharat has already created a distance of 14 m between himself and Charan. When Bharat reaches the endpoint, ie. after another 20 m, the distance between him and Charan is 21m ie. another 7 m.

So every 20 m, Bharat is creating a distance of 7 m between himself and Chara. to create a distance of 21m between himself and Charan, he must have to run a total of 60m. so the race must be 60m.

Therefore, the race must be of 60m.

#SPJ2

Similar questions