Three resisitors having resistance of 5 ohm 10 ohm and 30 ohm are connected in parallel and potential difference of 12 volt is applied across then obtain the current flowing through the circuit
Derive it
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Answered by
6
1/R=
1/5+1/10+1/30=1/3
therefore R=3 ohms
using the formula V=IR
12=I3
therefore I=12/3
=4 amperes
hope this helps
1/5+1/10+1/30=1/3
therefore R=3 ohms
using the formula V=IR
12=I3
therefore I=12/3
=4 amperes
hope this helps
Answered by
1
The answer is 0.218A
Let the equivalent resistance of the parallel resistants is 'R'.
So, 1/R = 1/5+1/10+1/15 =11/30
Thus, R=30/11 ohms.
CURRENT flowing through the circuit- i=R/V =(30/11)/12 A =0.218A
Let the equivalent resistance of the parallel resistants is 'R'.
So, 1/R = 1/5+1/10+1/15 =11/30
Thus, R=30/11 ohms.
CURRENT flowing through the circuit- i=R/V =(30/11)/12 A =0.218A
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