Question

Three resistan 10x 5x
2x are connected in series, what is
effective resistance?​

Answer 1

Answer:

Given,

R

1

=5Ω, R

2

=3Ω, R

3

=2Ω, V=10 Volt

Effective resistance of series combination.

R

s

=R

1

+R

2

+R

3

=10Ω

Now,

Current in Circuit I=I=

R

s

V

=

10

10

=1A

Voltage drop across R

1

, V

1

=IR

1

=1×5=5V

Voltage drop across R

2

, V

2

=IR

2

=1×3=3V

Voltage drop across R

3

, V

3

=IR

3

=1×2=2V

Answer 2

Answer:

R1 = 10 Ω

R2=5Ω

R3=2Ω

1/R = 1/R1 +1/R2+1/R3

1/R = 1/10+1/5+1/2

1/R = (1+2+5)/10

1/R = 8/10 = 4/5

R = 5/4 Ω

thus effective resistance R = 5/4 Ω