Question

Three resistance 14.5 Ω, 25.5 Ω and 60 Ω are connected in series across 200 V. What will be the voltage drop across 14.5 Ω​

Answer 1

Total current flowing through these three resistors

will be 14.5 + 25.5 + 60 => 100 ohms

now R × I = V

therefore I = V/R

=> I = 200/100 => 2 amps

since current flowing in series circuit is always same,

we have current flowing through all the three resistors

is same ie 2 amps

hence voltage from across 14.5 ohm resistor wii be

14.5 × 2 => 29 Volts