Three resistance 15 ohm,20 ohm,and 10 ohm are connected in parallel. Find the effective resistance of the circuit.
Answers
Answered by
100
R1 = 15 ohm
R2 = 20 ohm
R3 = 10 ohm
In Parallel combination
1 / Equivalent Resistance = 1/R1 + 1/R2 + 1/R3
=> 1/ Req = 1/15 + 1/20 + 1/10
=> 1/ Req = (4+3+6)/60
=> 1/ Req = 13/60
=> Req = 60/13
=> Equivalent Resistance = 4.6 ohm
R2 = 20 ohm
R3 = 10 ohm
In Parallel combination
1 / Equivalent Resistance = 1/R1 + 1/R2 + 1/R3
=> 1/ Req = 1/15 + 1/20 + 1/10
=> 1/ Req = (4+3+6)/60
=> 1/ Req = 13/60
=> Req = 60/13
=> Equivalent Resistance = 4.6 ohm
Answered by
72
Hello friend
--------------------------
Let's write the given
R1 = 15 ohm
R2 = 20 Ohm
R3 = 10 ohm.
We have to find the effective resistance in parallel (Rp) = ??
So,we know that,
1/Rp = 1/R1 + 1/R2 + 1/R3
By putting the value,
1/Rp = 1/15 + 1/20 + 1/10
1/Rp = 4 + 3 + 6/60
1/Rp = 13/60
Rp = 60/30
Rp = 4.615 ohm approximately.
Therefore, the effective resistance in the circuit is 4.615 ohm .
Thanks.
--------------------------
Let's write the given
R1 = 15 ohm
R2 = 20 Ohm
R3 = 10 ohm.
We have to find the effective resistance in parallel (Rp) = ??
So,we know that,
1/Rp = 1/R1 + 1/R2 + 1/R3
By putting the value,
1/Rp = 1/15 + 1/20 + 1/10
1/Rp = 4 + 3 + 6/60
1/Rp = 13/60
Rp = 60/30
Rp = 4.615 ohm approximately.
Therefore, the effective resistance in the circuit is 4.615 ohm .
Thanks.
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