Question

Three resistance 20 ohms, 30 ohms and 60 ohms are connected in series, their equivalent combination is *

1 point

20 ohms

110 ohms

50 ohms

10 ohms

​

Answer 1

The equivalent resistance for a series combination is calculated by summing up their respective magnitudes.

Thus, for a series combination, the equivalent resistance is:

R(eq) = R1 + R2 + R3

R(eq) = 20 + 30 + 60

R(eq) = 110 Ω

Hence, the equivalent resistance is 110 Ω.

Therefore, Option(B) is correct.

Answer 2

Answer:

$\huge\mathcal{\red{Hola! }}$

$\huge{\green{Answer}}$

$\huge\mathcal{\red{ 110 \ ohms}}$

Explanation:

When several resistors are joined in series, the resistance of the combination $R_s$ equals the sum of their individual resistors, $R_1$ , $R_2$ , $R_3$ , and is thus greater than any individual resistance.

$\huge\mathcal{\red{Therefore,}}$

The equivalent combination is:

20 ohms + 30 ohms + 60 ohms = 110 ohms.

$\huge\mathcal{\green{All \ the \ very \ best}}$

$\huge\mathcal{\red{@TheDynamicPrincess}}$