Three resistance 5000, 500, 50 ohm are connected in series across 550 volt mains, the current
flowing through them will be
(a) IA
(b) 100mA
(c) 10mA
(d) 10A
Answers
Answered by
11
Answer:
Current flowing through them is 0.099A
Explanation:
In series circuit
Total resistance, R =sum of resistance
=5000+500+50=5550ohm
Voltage V =550V
Current is same in all resistors
According to ohms law,
I =V/R =550/5550
= 0.099A
Current flowing through them is 0.099A
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