three resistance each of 4 ohm are connected in the form of an equilateral triangle. the effective resistance between two corners is?
Answers
Answered by
38
the answer is 8/3.
two resistance are in series...4+4=8.....now this resistance and 3rd resistance is in parallel.....8*4/(8+4)....solve this u will get 8/3
two resistance are in series...4+4=8.....now this resistance and 3rd resistance is in parallel.....8*4/(8+4)....solve this u will get 8/3
Answered by
25
★ Ello ★
here is your answer !!
here there is formation of equilateral traingle
now ,
look this attachment :-
1 / Rab= 1 /8 + 1 /4
=> 8 / 3 Ω
hope it helps you dear !!!
here is your answer !!
here there is formation of equilateral traingle
now ,
look this attachment :-
1 / Rab= 1 /8 + 1 /4
=> 8 / 3 Ω
hope it helps you dear !!!
Attachments:
Anonymous:
8/3 is the right answer mates :')
yes but thanks both of you.
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