Question

three resistance of 10 ohms are connected in series then value of equivalent resistance will be ?​

Answer 1

Answer:

30$\Omega$

Solution:

It is given that 3 resistors are connected in series connection and we are asked to find equivalent resistance.

Let us consider 3 resistors be R1, R2, R3. We know that equivalent resistance in series connection can be expressed as follows:

$\sf{ Resistance_{(series) }=R_1+R_2+R_3}$

Now put the values of resistors

$\sf{ Resistance_{(series) }=10\Omega + 10\Omega + 10\Omega}$

$\sf{ Resistance_{(series) }=30 \Omega$

So the required equivalent resistance is combination is 30$\bf\Omega$.

Additional information:

Resistance in parellel connection can be expressed as:

$\sf\dfrac 1 R_{(Parellel)}=\dfrac 1 R_1+ \dfrac 1 R_2+ \dfrac 1 R_3\dots\dots$