three resistance of 2 ohm 3 ohm and 5 ohm are connected in the electric circuit ,calculate the (1)maximum effective resistance (2)minimum effective resistance
Answers
Answered by
113
maximum effective resiatance will be
By series connection
2 ohm +3ohm+5 ohm =10 ohm
minimum effective resistance will be
By parallel connection
1/2ohm +1/3 ohm +1/5 ohm =
1.03 ohm
By series connection
2 ohm +3ohm+5 ohm =10 ohm
minimum effective resistance will be
By parallel connection
1/2ohm +1/3 ohm +1/5 ohm =
1.03 ohm
Answered by
5
Answer:
Three resistors are connected in parallel
The three resistors are 2, 3, and 5 ohms
Solution:-
Apply the formula of parallel,
1/R=1/R1+1/R2+1/R3
1/R=1/2+1/3+1/5
1/R=15/30+10/30+6/30
1/R=31/30
R=30/31 = 0.967 ohm
Explanation:
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