Three resistance of 2W, 3Wand 5Ware connected in the electric circuit. Calculate the
(1) Maximum effective resistance
(2) Minimum effective resistance
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Answer:
1) max effective resistance = 10
2) min effective resistance = 0.97
Explanation:
1) for max resistance, all three resistance should be attached in series combination
therefore, R=R1+R2+R3
R= 2+3+5= 10
2) for min effective resistance, all three resistance should be attached in parallel combination
1/R= 1/R1 +1/R2+1/R3
1/R= 1/2+1/3+1/5 (taking LCM of 2,3,5)
1/R= (15+10+6)/30
1/R=31/30
R= 30/31
R= 0.97
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