Three resistance of 30 ohm,10 ohm and 5 ohm are connected in parallel with 6 volt battery then calculate:total current drawn from the battery e and
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GIVEN THAT - R1 = 30 ohm
R2 = 10 Ohm
R3 = 5 ohm
V = 6 volt
TO FIND ----) Total current ( I net ) - ??
A.T.Q Three resistance are connected in parallel so by parallel combination ,
1 / Req = 1 / R1 + 1 /R2 + 1 / R3
1 / Req = 1 / 30 + 1 / 10 + 1 / 5
1 / Req = ( 1 + 3 + 6 ) / 30 = 10 / 30 = 1 / 3
Req = 3 ohm
So by ohms law , V = I X R , I = V / R
I net = 6 / 3 = 2 Ampere
Total current flowing is 2 ampere in the circuit
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