Question

Three resistance of 5 10 and 15 ohm are connected in series and a potential difference of 15 volt is applied across the extreme ends calculate the current passing through the circuit

Answer 1

here sum of all resistances = 5+10+15= 30

voltage i.e v=15

I = v/r

I = 15/30

I = 1/2 = 0.5 A

Answer 2

i=v/r
i=15/total resistance = 30
i=15/30

i=0.5