Question

three resistance of 5 ,10 and 15 ohms are connected in series and potential difference of 15 volt is applied across the extreme end . calculate the current passing through the circuit

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Answer 1

Answer :

• The current flowing in the circuit is 0.5 A.

Explanation :

Given :

• Resistance in the resistor, R₁ = 5 Ω
• Resistance in the resistor, R₂ = 10 Ω
• Resistance in the resistor, R₃ = 15 Ω
• Voltage in the circuit, V = 15 V

To find :

• Current in the circuit, I = ?

Knowledge required :

Since we know that the, current flowing in a series is same in throughout the circuit.

So we will find the equivalent resistance in the circuit and then by using the ohm's la, we can find the current passing through the circuit.

• Formula for total resistance in a series circuit :

⠀⠀⠀⠀⠀⠀⠀⠀⠀R₁ + R₂ + R₃ + ... + Rₙ = R'⠀

[Where : R' = Equivalent resistance in the series circuit, R = Resistance in the resistors]

• Ohm's law (equation) :

⠀⠀⠀⠀⠀⠀⠀⠀⠀V = IR⠀

[Where : V = Potential difference, I = Current, R = Resistance]

Solution :

First let us find the equivalent resistance in the circuit.

⠀By using the formula for total resistance in a series circuit and substituting the values in it, we get :

⠀⠀=> R₁ + R₂ + R₃ = R'

⠀⠀=> 5 + 10 + 15 = R'

⠀⠀=> 30 = R'

⠀⠀⠀⠀⠀∴ R' = 30 Ω

Hence the equivalent resistance in the circuit is 30 Ω.

Now let us find the current in the circuit.

⠀By using the ohm's law and Substituting the value in it, we get :

⠀⠀=> V = IR

⠀⠀=> 15 = I × 30

⠀⠀=> 15/30 = I

⠀⠀=> 0.5 = l

⠀⠀⠀⠀⠀∴ I = 0.5 A

Therefore,

• Current in the circuit, I = 0.5 A

Answer 2

Answer:

Explanation:

Given,

Resistance in the resistor, R₁ = 5 Ω

Resistance in the resistor, R₂ = 10 Ω

Resistance in the resistor, R₃ = 15 Ω

Voltage, V = 15 V

To Find,

Current passing through the circuit.

Formula to be used,

Total Resistance, R' = R₁ + R₂ + R₃

Ohm's Law, V = IR

Solution,

Putting all the values, we get

At 1st here we have to find the equivalent resistance,

R' = R₁ + R₂ + R₃

⇒ R' = 5 + 10 + 15

⇒ R' = 30 Ω

Now, current passing through the circuit ,

V = IR

⇒ 15 = I × 30

⇒ 15/30 = I

⇒ 0.5 A = l

Hence, the current passing through the circuit is 0.5 A.