Question

three resistance of 9 ohm are comnected so that total resistance become 1) 3 ohm (2)27 ohm (3) 13.5 ohm​

Answer 1

◀◀ HELLO ▶▶

HERE IS THE 3 SITUATION

1) 3 Ohms

⚫ When all the resistance are connected parallely Its Net result is 3 ohms

$\large\purple{ = > \frac{1}{R} = \frac{1}{9} + \frac{1}{9} + \frac{1}{9 } = > \frac{3}{9} } \\ \\ => R = 3$

2) When All the resistance Connected or Joined in series its Equivalent result is 27 Ohms

$\large\purple{=> R = 9 + 9 + 9 = > 27 \: Ohms}$

3) When 2 Resistance Joined paralely and one with Series

$\large\pink{=> \frac{1}{R} = \frac{1}{9} + \frac{1}{9} = > \frac{2}{9} = 4.5} \\ \\ {= > \: 4.5 \: + 9 \: = 13.5 \: Ohms}$

Answer 2

Answer:

Explanation:

resistance of each wire=9ohm

1)3ohm

by arranging it in parallel

1/9+1/9+1/9

=3/9

=1/3

=3 ohm

2)27 ohm

by arranging it in series

9+9+9

=27 ohm

3)13.5 ohm

by arranging 2 in parallel and 1 in series

1/9+1/9

=2/9

=9/2

9/2+9

=(9+18)/2

=27/2

=13.5 ohm

HOPE IT HELPS