Three Resistance of values 2 ohm, 3 Ohm
and 5 ohm
Connected in series
across
20 VD.C supply calculate
b)the power dissipated in each resistor
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Explanation:
now, now I = 20
so, 1)P=I²R = 400×2=800W
similarly,
2)P=I²R=400×3=1200W
and,
3)P=I²R=400×5=2000W
hope it helps!
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