Question

three resistance R1, R2 and R3 are such that R2 is double and R3 is triple of R1. if all are connected in parellel then the resistance of the combination is how many times that of R1 ​

Answer 1

Answer:

In series combination, the current passing through each resistor will be the same.

V = V1 + V2 + V3

V = IR1+ IR2 + IR3

V = I (R1 + R2 + R3)

V/I = R1 + R2 + R3

Therefore,

R = R1 + R2 + R3

In parallel combination, potential difference across each resistor will be same

I = I1 + I2 + I3

I = V/R1 + V/R2 + V/R3

I/V = 1/R1 + 1/R2 + 1/R3

Therefore,

1/R = 1/R1 + 1/R2 + 1/R3

Explanation: