three resistance Rohm,8ohm and 12 ohm connected in a series in a circuit if the resultant resistance in the circiut of 20ohm find the value of R,1
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Answer:
R1= 0 ohm
Explanation:
Given-R2=8 ohm
R3=12 ohm
R.R=20 ohm
Now by formula of equivalent resistance of series combination of resistors
R.R=R1+R2+R3
20=R1+8+12
20=R1+20
20-20=R1
R1=0 ohm
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