Three resistances 12 ohms each are connected in parallel. Three such combinations are connected in series. What is the total resistance?
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Resistance of three resistors in parallel
1/R = 1/12 + 1/12 + 1/12 + 1/12
1/R = 4/12
1/R = 1/3
R = 3 ohms
Three such combinations are connected in series
Total resistance = 3 + 3 + 3 = 9 ohms
So total resistance of the combination is 9 ohms.
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Explanation:
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