Three resistances 2Ω, 3Ω and 6Ω are connected
in parallel to a 20 V battery. The electric
current in circuit is?
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Answer: 20 A
Concept: Ohm’s Law
The relationship between electric current and a potential difference is stated by Ohm's law. Most conductors have a direct relationship between the voltage applied to them and the current that flows through them.
Given: R1= 2Ω R2=3Ω R3= 6Ω V= 20 V
To Find: Current (I)
Step-by-step explanation:
As the three resistances i.e. R1, R2, and R3 are connected in parallel series, we will first find the overall resistance.
1/RP= 1/R1+1/R2+1/R3
1/RP=½+⅓+⅙
1/RP= 3+2+⅙
1/RP= 6/6
RP=1 Ω
Now, as per Ohm’s law
V=IR
Where, V= Potential difference, I = Current, R= Resistance
Now, placing the values in the above formula
We get
20=(I) 1
I= 20 A
The electric current in the circuit is = 20 A
Project code: #SPJ2
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