Question

Three resistances 5000, 500, 50 ohms are connected in series across 550v .the current flowing through them will be?

Answer 1

$\huge\mathcal{\fcolorbox{aqua}{blue}{Answer࿐}}$

$\huge\mathfrak\pink{Given:}$

Resistor of 5000 Ω , 500 Ω , 50 Ω

$⇒R_{t} = R_{1} + R_{2} + R_{3} \: \: \: \: \: \: \: \\ ⇒R_{t} = 5000 \: + \: 500 \: + 50 \\⇒R_{t} = 5500 \: Ω \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$⇒V = \: I R \\ \\ ⇒I = \frac{V}{R} \: \: \: \\ \\ ⇒I = \frac{550}{5550} \\ \\ ⇒I = 0.099 \: amp \: (approx) \:$

$\huge\mathcal\color{Yellow}I\: hope\:it\:helps\:you.$