Question

Three resistances each equal to 5 ohm are connected I. series with a cell of 1.2V find the magnitude of current in the circuits​

Answer 1

Answer:

0.08ampere

Explanation:

apply the formula of resistance equivalent for parallel Req=R1 +R2+... ie 5+5+5=15.V=IR,I=V/R,I=1.2/15=0.08A