Question

Three resistances each of 2Ω, 3Ω & 5Ω are connected in series as well as in parallel. Calculate the equivalent resistance for both cases.​

Answer 1

Explanation:

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Answer 2

Answer:

Explanation:

resistance in series R1+R2+R3=R

                   2+3+5=10 ohm

resistance in parallel 1/R1+1/R2+1/R3=1/R

                       1/2+1/3+1/5=1/R

                         28/30=1/R

                        R=15/14 ohm