Three resistances each of 3ohm are connected in series. The eqiivalent resistance of the series is:
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eqiivalent resistance of the series = r1+ r2+ r3
therefore equalent resistance = 3+3+3
=9ohms
❤ hope this answer helps ❤
therefore equalent resistance = 3+3+3
=9ohms
❤ hope this answer helps ❤
Answered by
1
Here it is given that three resistance of 3 ohm each are connected in series
We have to find out the total resistance
Let R1, R2, and R3 be the 3 resistances
Now, to find the total resistance of resistances that are connected in series
We have to simply add the resistances
Here, total resistance = R1 + R2 + R3
= 3 + 3 + 3
= 9
Hence, the total resistance will be 9 ohm
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