Question

Three resistances of 2, 3 and 5 Ω are connected in parallel to a 10 V battery of negligible internal resistance. The potential difference across the 3 Ω resistance will be

Answer 1

Answer:

Total resistance=10 ohm

Relationship using ohms law=

I=E/R

I=10/10

I=1A

Potential drop across 3 ohm resistor =

V,Potential difference=1×3=3V

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Answer 2

Answer:

Total resistance=10 ohm

Relationship using ohms law=

I=E/R

I=10/10

I=1A

Potential drop across 3 ohm resistor =

V,Potential difference=1×3=3V

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