Question

Three resistances of 2 ohm, 4 ohm and 6 ohm are connected in series, calculate the effective resistance.

Answer 1

Answer:

Given : R

1

=2Ω R

2

=4Ω R

3

=6Ω

Parallel combination :

Equivalent resistance

R

p

1

=

R

1

1

+

R

2

1

+

R

3

1

R

p

1

=

2

1

+

4

1

+

6

1

⟹ R

p

=

11

12

Ω

Series Combination :

Equivalent resistance R

s

=R

1

+R

2

+R

3

=2+4+6=12Ω