three resistances of 2ohm, 3ohm and 6ohm (1) in series (2) in parallel
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Answered by
1
Answer:
in series
Re = R1 + R2+R3
= 2+3+6
=11
in parallel
1/Re = 1/R1+1/R2+ 1/R3
1/Re = 1/2+1/3+1/6
1/Re = 6/6
1/Re= 1
Re = 1
Answered by
1
Answer:
in series
the total resistence will be
2+3+6(ohm)
= 11 ohm
whereas the total resistence in parallel connection
1/2+1/3+1/6
I/rp= 6/12+4/12+2/12
1/rp= 12/12
rp=12/12
= 1 ohm
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