Question

Three resistances of 4Ω, 8Ω 16Ω are connected in a parallel to a 220 V

supply. Calculate the equivalent resistance and current in circuit?​

Answer 1

Answer:

(a) For Parallel connection,

R

p

1

=

R

1

1

+

R

2

1

+

R

3

1

R

p

1

=

2

1

+

4

1

+

5

1

R

p

1

=

20

10+5+4

R

p

=

19

20

Ω

(b) R

1

=2Ω,R

2

=4Ω,R

3

=5Ω

I

1

=

R

1

V

=20/2=10A

I

2

=

R

2

V

=20/4=5A

I

3

=

R

3

V

=20/5=4A

Total current = I

1

+I

2

+I

3

=19A

Answer 2

1. formula = 1/R1 + 1/R2 + 1/R3 = 1/Rp answer is Rp.
2. by applying the formula we get, 1/4 +1/8 +1/16 = ( 4+2+1 ) /16 hence, 1/Rp= 7/16 .so final resistance is 16/7
3. current = V/R
4. current = 220 /( 16/7) = 96.25 A
5. please follow me please