Question

three resistances of 4 ohm,6 ohm and 10 ohm are connected in parallel with a battery emf of 4.53 V.if current through 6 ohm resistance is 0.6A the internal resistance of the battery is​

Answer 1

Answer:

By putting values in the formula I = E/(R+r)....(1), u will get the values of internal resistance of Battery.

Explanation:

1/R= 1/R1 + 1/R2 + 1/R3 = 1/4 + 1/6 + 1/10 => R = 1.93

I2 = 0.6A ( given )

V2 = I2 * R2 = 0.6 * 6 = 3.6v

As it is parallel connection of resistors so voltage is same, V1=V2=V3=3.6v

so,  I1= V1/R1 = 3.6/4 =0.9A

I3=V3/R3= 3.6/10= 0.36A

I= I1+I2+I3 = 0.9+0.6+0.36 = 1.86A

By putting values in above formula (1);

I = E/(R+r)

1.86 =4.53/ (1.93+r)

r = 0.5 ohm ''Ans''