Question

Three resistence are 5ohm,10ohm,and 15 ohm are connected in series and potential of 15 volts.Find the current flowing to the circuit.​

Answer 1

$\bf{\underline{\underline \green{AnswEr:-}}}$

R = R1 + R2 + R3 = 30Ω

I = V/R = 30 / 30 = 1A

V across 10Ω = IR2 = 1 × 10 = 10 V

Answer 2

Answer:

0.5 A or 1 / 2 A

Explanation:

Given that:

R₁= 5 ohm

R₂ = 10 ohm

R₃  = 15 ohm

potential = 15 V

So Equvivalent resistance will be

R₀ = R₁ + R₂ + R₃

    = 30 ohm

So, current will be

(V = IR₀)

I = V / R₀

I = 15 volts / 30 ohm

I = 0.5 or 1 / 2 ampere

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