Three resister 1ohm2ohm3ohm are connected in series what is the total resister of the combination
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Answer:
R= R1 +R2+R3
R= 1+2+3
R= 6ohm
Answered by
0
Answer:
6Ω
Explanation:
R1=1Ω
R2=2Ω
R3=3Ω
resistor connected in series
Rs=R1+R2+R3
= 1Ω+2Ω+3Ω
=6Ω
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