three resistirs having resistances of 3 ohm ,6ohm,12 ohm are connected in both parallel and in series potential difference of 12 V is applied across them calculate effective resistance and current flowing through both the circuit
Answers
Answered by
0
Answer:
effective resistance is 22.7 1 and current flowing in the circuit is 1.89 A.
Answered by
0
Answer:
Resistance in series= 3+6+12
=21 ohm
V = 12V
I=V×R
= 252A
R in parallel= 1/3 +1/6 +1/12
R= 12/7 ohm
I= V×R
= 20.5A
Similar questions