Three resistor 3 ohms ,4 ohms and 5 ohms are joined in a parallel in an electric circuit.If a current of 150mA flow through resistor 4 ohms then calculate the value in mA which will be flowing through other two resistors.
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We know that in // ckt voltage is same.. Show take voltage v
In 4ohm resistor current flow 150mA.
Show...v=ir
v = 150*4
=600v
Now
In 3 ohm resistor current flow...
V=ir
600=i*3
i = 200mA
In 5 ohm
600=i*5
i=120 ma
In 4ohm resistor current flow 150mA.
Show...v=ir
v = 150*4
=600v
Now
In 3 ohm resistor current flow...
V=ir
600=i*3
i = 200mA
In 5 ohm
600=i*5
i=120 ma
Justinlover2004:
Thank you
Most welcome
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