Question

three resistor are 12 6 3 ohm are connected in series​

Answer 1

Answer:

Given-

R1 = 4ohm

R2 = 6ohm

R3 = 12ohm

Rs = 2ohm (Series resistor)

Potential difference,V = 6V

Let the resistance of all three resistors which are connected in parallel be Rp

Then,

1/Rp = 1/R1 +1/R2 + 1/R3

1/Rp = 1/4 + 1/6 + 1/12

1/Rp = 6/12

or,Rp = 12/6 = 2ohm

Let total resistance be Rt = Rp +Rs

Rt = 2 + 2 = 4ohm

a).So current,I in the main circuit will be V=IR

therefore, I = V/R = 6/4 = 1.5A which is total current.

b) Since in parallel the current will divided into three resistors connected in parallel.Let the current across all the three be I1,I2 and I3.

Now,

I1 = V/R1 (Since potential difference is same as they are connected in parallel)

I1 = 6/4 = 1.5A

Similarly,I2 = V/R2

I2 = 6/6 = 1A

and I3 = 6/12 = 0.5A

c). V across 2ohm resistor will be-

V = I*R ( I will be total current)

V = 1.5 * 2 = 3V