Question

three resistor each of resistance 6 ohm are arranged to give 9 ohm combination give the possible circuit diagram​

Answer 1

Given :

➳ We have been provided three identical resistors each of resistance 6Ω.

To Find :

➢ We have to arrange them in such a way to get equivalent resistance equal to 9Ω

Diagram :

✪ Refer the attachment for better understanding.

Need to know :

✴ Eq. resistance of series connection :

$\bigstar\:\underline{\boxed{\bf{R_s=R_1+R_2+...+R_n}}}$

✴ Eq. resistance of parallel connection :

$\bigstar\:\underline{\boxed{\bf{\dfrac{1}{R_p}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+...+\dfrac{1}{R_n}}}}$

SoluTion :

↗ A and B are in parallel connection :

$:\implies\sf\:\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$:\implies\sf\:\dfrac{1}{R}=\dfrac{1}{6}+\dfrac{1}{6}$

$:\implies\sf\:\dfrac{1}{R}=\dfrac{2}{6}$

$:\implies\bf\:R=3\Omega$

↗ (AB) and C are in series :

$:\implies\sf\:R_{eq}=R+R_3$

$:\implies\sf\:R_{eq}=6+3$

$:\implies\underline{\boxed{\bf{R_{eq}=9\Omega}}}$

Answer 2

Answer:

two resistance in parallel and one in series with the resultant of parallel