Question

three resistor of 3ohms,6ohms,9ohms,are connected in parallel. calculate total resistance of the circuit​

Answer 1

Explanation:

1/R = 1/3 + 1/6 +1/9

1/R = { 12 + 6 +4 }/36

1/R = 22/36

R = 18/11

Answer 2

Answer:

Explanation:

the total resistance is 1.33 ohm

1/Rp=1/R1+1/R2+1/R3

1/Rp=1/3+1/6+1/4

1/Rp=4/12+2/12+3/12

1/Rp=9/12

1/Rp=3/4

Rp=4/3

Rp=1.33 ohm