Question

Three resistor of values 2 ohm, 4ohm, 6ohm, are connected in series. The equivalent resistance of combination of resistors is

Answer 1

Answer:

12 ohm

Explanation:

If they are connected in series u have to add the resistances

Answer 2

Answer: The equivalent resistance of the combination of resistors is 12Ω.

Explanation:

The values of resistance given in the question are,

R₁=2Ω

R₂=4Ω

R₃=6Ω

In a series combination, the current through each resistor is the same but the voltage is different. i.e.

$V_e_q=V_1+V_2+V_3$              (1)

Let's find the individual voltages of the given resistors,

V₁=I×2

V₂=I×4

V₃=I×6

And Veq=I×Req

By substituting V₁, V₂, V₃and Veq in equation (1) we get;

$I\times R_e_q=I\times2+I\times4+I\times6$

$R_e_q=2+4+6=12\Omega$

Hence, the equivalent resistance of the combination of resistors is 12Ω.