Question

Three resistors 1 ohm, 2 ohm and 3 ohm are connected in series with a battery of 6V. Find net current in circuit and potential difference across 2 ohm resistor.​

Answer 1

we know connected in series resistance

Resistance equal=R1+R2+RE

so R equilaent =1+2+3=6 ohm

so current=voltage/R equilaent

1.

so current=6/6=1 ampere

2.potential difference across 2ohm=current x resistance=6x2 =12 v

thank you

Answer 2

Here all of them are in series hence,
Total resistance=1+2+3 ohm=6 ohm
And V=IR
Hence I=6/6=1
Potential diff across the 2 ohm resistor:
V=1*2=2 V
Hence the potential difference across the 2 ohm resistor is 2 Volts.