Three resistors 10 ohm ,20 ohm and 60 ohm are connected in parallel. the combination is connected to a battery of 30 volts . find the current through the circuit and the current through each resistor
Answers
a) Current through each resistor:
For parallel combination of resistor, potential difference across each resistor is same.
Current through 10 Ω resistor is,
V = IR
V= 9V
R =10 Ω
Thus, I1 = 9/10 = 0.9 A
Current through 20 Ω resistor,
I2 = 9/20 = 0.45 A
Current through 30 Ω resistor is,
I3 = 9/30 = 0.3 A
b) Total current in the circuit is,
I = I1+ I2 + I3 = 0.9 + 0.3 + 0.45 = 1.65 A
Thus, total current flowing through the circuit is 1.65 A.
c) Effective resistance:
The resistors are connected in parallel,
Thus,
1 over R subscript p equals 1 over 10 plus 1 over 20 plus 1 over 30
fraction numerator begin display style 1 end style over denominator begin display style R subscript p end style end fraction space equals space 11 over 60
T h u s comma
R subscript p space equals space 5.45 space capital omega
Thus, the effective resistance of the circuit is 5.45 Ω