Three resistors 2 3 4 are combined in parallel what is total resistance of combination
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Answered by
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Hey mate!
I am here with your answer!
Given, there are 3 resistors
R1 = 2 ohm
R2 = 3 ohm
R3 = 4 ohm
are connected in parallel combination.
Then the equivalent resistance will be=
1/R = 1/2 + 1/3 + 1/4
1/R = 6 + 4 + 3 / 12
1/R = 13 / 12
R = 12 / 13
R = 0.92 ohm.
The equivalent resistance will be 0.92 ohm.
Hope this will help you!
Answered by
0
1/R=1/2+1/3+1/4
1/R=13/12
R=12/13 ohm
Please mark it brainliest
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