Question

Three resistors 2 Ω, 4 Ω and 5 Ω are combined in parallel. What is the total resistance of the combination?​

Answer 1

Answer:

2+4+5 11 ohms is the answer

Answer 2

Given :-

• Three resistors R1 = 2 Ω, R2 = 4 Ω and R3 = 5 Ω are combined in parallel.

To Find :-

• The total resistance of the combination.

Solution :-

The total resistance of the above circuit can be calculated by the following formula,

$\red \bigstar \: \sf\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{ R_3}$

[ Putting values ]

$\longrightarrow \sf \: \frac{1}{R} = \frac{1}{2} + \frac{1}{4} + \frac{1}{5}$

$\longrightarrow \sf \: \frac{1}{R} = \frac{10 + 5 + 4}{20}$

$\longrightarrow \sf \: \frac{1}{R} = \frac{19}{20} \: \Omega \: \: \green\bigstar$

Hence,

• Total resistance of the parallel combination is 19/20 Ω.