Three resistors 2 Ω, 4 Ω and 5 Ω are combined in parallel. What is the total resistance of the combination?
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Answered by
3
Hey mate here ur answer....
1/R = 1 / 2 + 1 / 4 + 1 / 5
1 / R = 19 / 20
R = 20 / 19
R = 1.05 ohm
1/R = 1 / 2 + 1 / 4 + 1 / 5
1 / R = 19 / 20
R = 20 / 19
R = 1.05 ohm
Answered by
1
» As ; all are connected in PARALLEL .. SO ; POTENTIAL DIFFERENCE ACROSS ALL RESISTORS IS SAME . I¹ ( Current in 5Ω Resistor ) = V / R = 6 / 5 = 1.2 Ampere. V / R = 6 / 30 = 0.2 Ampere .
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