Question

three resistors 2ohm,3ohm and 4ohm are connected in parallel such that the total current through them is 2.08A.calculate the current through each resistor.

Answer 1

nce this parallel combination is connected with a cell, the potential difference through each resistor will be 2 volts. Now using I=V/R,

current through 3 ohm resistor = 2/3

current through 4 ohm resistor = 2/4

current through 6 ohm resistor = 2/6

And the total current will be the sum of individual current in each resistor using Kirchoff’s junction law, Total current = 2/3 + 2/4 + 2/6 = 3/2 or 1.5 ampere

Answer 2

Hey dear friend

First we find R equivalent
As resistors are in parallel then,

1/r1+1/r2+1/r3=
1/2+1/3+1/4=12/13 ohm

Now. By the formula
V=I*R
V=2.08*12/13
V=1.92volt

Now the current of individual resistor
V=I*r1
1.92=I*2
I=0.96A of r1

V=I*r2
1.92=I*3
I=0.64A of r2

V=I*r3
1.92=I*4
I=0.48A of r3

perfectly fine pure correct answer
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