Three resistors 2ohm, 3ohm and 4ohm are connected in series. This combination is connected to the source of emf 10V. What is the potential drop across each resistor?
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Answer:
at 2 ohm v= 10/9*2= 20/9= 2.2
at 3 ohm v= 10/9× 3= 10/3= 3.3
at 4 ohm v= 10/9× 4= 40/9= 4.4
Explanation:
first we calculate the net resistance of the circuit which is 9 ohm then the current in the circuit which is 10 by 9 then potential across each resistor is current x individual resistance
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