Question

three resistors 3 ohm 6 ohm 4 ohm are connected in parallel calculate the total resistance of the circuit​

Answer 1

the total resistance is 1.33 ohm

1/Rp=1/R1+1/R2+1/R3

1/Rp=1/3+1/6+1/4

1/Rp=4/12+2/12+3/12

1/Rp=9/12

1/Rp=3/4

Rp=4/3

Rp=1.33 ohm

Answer 2

total resistance = 1/R1 +1/R2 +1/R3

1/Rp = 1/3+ 1/6 + 1/4

1/Rp = 9/18 + 1/ 4

1/Rp = (36 + 18)/72

1/Rp = 54/72

therefore Rp = 72/54 = 4/3 = 1.33 ohm

hope this helps u....