Question

three resistors 4 ohm, 3 ohm, R and an ammeter are connected in series to a cell of 2 volt. If the reading of ammeter be 0.25 a then calculate the value of R​

Answer 1

Explanation:

v=IR

2=0.25*(4+3+R)

2=0.25*(7+R)

2*100/25=7+R

8=7+R

R= 8 ohms

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Answer 2

Answer:

As V=iR

net resistance=4+3+R ohm

Explanation:

2=(0.25)(7+R)

8=7+R

Therefore R=1 ohm

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