Question

Three resistors  5Ω, 10Ω and 30Ω are connected in parallel with the battery of Voltage  6V?

Calculate:
1. The value of current across each resistor.
2. The value of Potential difference across each resistor.
3. Total current in the circuit.
4. Effective resistance of the circuit.​

Answer 1

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Answer 2

Given:

• Resistance = 5Ω, 10Ω and 30Ω
• Voltage of battery = 6V

Find:

• The value of current across each resistor.
• The value of Potential difference across each resistor.
• Total current in the circuit.
• Effective resistance of the circuit.

Solution:

1)

we, know that

→ I = V/R

Current in resistor of 5Ω

⊙ I₁ = V/R

⊙ I₁ = 6/5 = 1.2 A

Current in resistor of 10Ω

⊙ I₂ = V/R

⊙ I₂ = 6/10 = 0.6 A

Current in resistor of 30Ω

⊙ I₃ = V/R

⊙ I₃ = 6/30

⊙ I₃ = 2/10 = 0.2 A

2)

● Potential difference across each resistor is 6V bcz it is a parallel circuit.

3)

we, use

☞ 1/R = 1/R₁ + 1/R₂ + 1/R₃

☞ 1/R = 1/5 + 1/10 + 1/30

☞ 1/R = (6 + 3 + 1)/30

☞ 1/R = 10/30

☞ 1/R = 1/3

☞ R = 3Ω

Total Current (I) = V/R

→ I = 6/3

→ I = 2A

4)

Total effective resistance will be 3Ω