Three resistors 5 Ω, 8 Ω and 11 Ω respectively are connected in series to a battery of 24 V. Draw the circuit diagram and calculate (a) the total resistance (b) the total current drawn from the battery (c) the p.d at the ends of each resistor.
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Explanation:
Equivalent resistance equal to 5 + 10 + 15 Ohm= 30 ohm I=V/R I=30/30 I=1A Current through 10 ohm resistor will remain same that is equal to the total current in the circuit because the resistor is connected in series Now potential difference in the 10 ohm resistor V=IR V=1*10 V=10
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